(8y^2+2)-(4-2y^2)=10y^2-2

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Solution for (8y^2+2)-(4-2y^2)=10y^2-2 equation: 


Simplifying
(8y2 + 2) + -1(4 + -2y2) = 10y2 + -2

Reorder the terms:
(2 + 8y2) + -1(4 + -2y2) = 10y2 + -2

Remove parenthesis around (2 + 8y2)
2 + 8y2 + -1(4 + -2y2) = 10y2 + -2
2 + 8y2 + (4 * -1 + -2y2 * -1) = 10y2 + -2
2 + 8y2 + (-4 + 2y2) = 10y2 + -2

Reorder the terms:
2 + -4 + 8y2 + 2y2 = 10y2 + -2

Combine like terms: 2 + -4 = -2
-2 + 8y2 + 2y2 = 10y2 + -2

Combine like terms: 8y2 + 2y2 = 10y2
-2 + 10y2 = 10y2 + -2

Reorder the terms:
-2 + 10y2 = -2 + 10y2

Add '2' to each side of the equation.
-2 + 2 + 10y2 = -2 + 2 + 10y2

Combine like terms: -2 + 2 = 0
0 + 10y2 = -2 + 2 + 10y2
10y2 = -2 + 2 + 10y2

Combine like terms: -2 + 2 = 0
10y2 = 0 + 10y2
10y2 = 10y2

Add '-10y2' to each side of the equation.
10y2 + -10y2 = 10y2 + -10y2

Combine like terms: 10y2 + -10y2 = 0
0 = 10y2 + -10y2

Combine like terms: 10y2 + -10y2 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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